Sunday, February 22, 2009

source code to show the int literals



// sample program to show the int literals

package literals;

public class IntLiteralExample {


public static void main(String[] args) {
int i='a';
int j=10;
byte b1='b';
char ch='b';
//int i=123.34 ------> not valid
//byte b=ch; ------>THIS STATEMENT GIVES ERROR (PLP found : char reqired: byte
System.out.println(i);
System.out.println(j);
System.out.println(ch);
//System.out.println(b);

}

}
output:
97
10
b


4 comments:

d said...

how int i='a' answer is 97

LakshmiNarayana Gorantla said...

because of Unicode. Every character have the unicode..here that unicode is convert to int and showing us

Sindhu Kamineni said...

In byte b=ch; why ch can't be assigned to byte. why It can't covert 'b' into 98.

Laxman G said...

char data type size is 2 bytes , we are assigning into 1 byte of byte data type so it won't allow..It won't consider what value is it..it will check size of the data type.

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