Shift Operator with byte data type source code

/* This  Program is a simple java Application showing how to
use shift operators on integer data types (byte)*/
package operators;

public class ByteWithShiftOperator {

    /**
     * @param args
     */
    public static void main(String[] args) {
        byte i=3; 
        //byte j =i <<3; error ??
        //left shift operator
        System.out.println(" i << 1 =" + (i <<1));
        System.out.println(" i << 3 =" + (i <<3));
    System.out.println(" i << 8 =" + (i <<8));//is this same as i ?
    System.out.println(" i << 9 =" + (i <<9)); //is this same as <<1 ?
    System.out.println(" i << 8 =" +(byte) (i <<8)); //???
    System.out.println(" i << 9 =" +(byte) (i <<9)); //???

        i=44;
        //right shift operator
        System.out.println(" i << 1 =" + (i >>1));
        System.out.println(" i >> 8 =" + (i >>8));
        i=127;
        System.out.println(" i >> 7 (i is 0xff) =" + (i >>7));
        System.out.println(" i >> 8 (i is 0xff) =" + (i >>8));
        // unsigned right shift
        System.out.println(" i >>> 7 (i is 0xff) =" + (i >>>7));
        System.out.println(" i >>> 8 (i is 0xff) =" + (i >>>8));
        System.out.println(" i >>> 8 =" + (i >>8));
        // all the above four yeilds the same result why ?
        i = -22 ;
        System.out.println(" i >> 1  =" + (i >>1));
        System.out.println(" i >> 3  =" + (i >>3));
        System.out.println(" i >>> 1  =" + (i >>>1));
        System.out.println(" i >>> 3  =" + (i >>>3));
           System.out.println(" i >>> 8  =" + (i >>>8));//same as i

    }

}


output:
i << 1 =6
 i << 3 =24
 i << 8 =768
 i << 9 =1536
 i << 8 =0
 i << 9 =0
 i << 1 =22
 i >> 8 =0
 i >> 7 (i is 0xff) =0
 i >> 8 (i is 0xff) =0
 i >>> 7 (i is 0xff) =0
 i >>> 8 (i is 0xff) =0
 i >>> 8 =0
 i >> 1  =-11
 i >> 3  =-3
 i >>> 1  =2147483637
 i >>> 3  =536870909
 i >>> 8  =16777215